North

QJT9

J32

K97

842

East

A8653

9764

AQ52

-

West

42

AKQ

J6

AKQT97

South

K7

T85

T843

J653

Len Dixon played with us on New Year's Eve and encountered this hand. Here is how he wrote it up for the Canberra Times:

Today's deal came up on New Year's Eve in a matchpoint pairs session at the Batemans Bay Bridge Club. Created, as is nowadays usual, by a computer program that "shuffles" the cards far more thoroughly than lazy humans but "understands" nothing about bidding and card play, it is for all practical purposes a truly random deal.

The contract at four of seven tables was 3NT, twice by East and twice by West. No two declarers made the same number of tricks. Results ranged from one down to two overtricks. On hand records distributed at the end of the session, the Deep Finesse software package revealed that, if everyone could see all 52 cards and played perfectly, one overtrick would ensue.

When, at some point in the (unrecorded) auctions at two other tables, West saw fit to show his/her threadbare four-card major, East fell in love with AKQ of Hearts and they became became trumps. Each West made 10 tricks which earned two-thirds of the match points for the pair in 4 Hearts but none at all for the pair in 6 Hearts, a poor slam (against unknown NS holdings) which improves considerably when trumps split three-three, especially if North hasn't led a spade. After, say, a club lead declarer inserts dummy's 9 of Clubs, trumps South's J of Clubs and cashes the Heart AKQ. When NS both follow throughout, spade 8653 diamond 2 are discarded on Clubs and the losing Diamond finesse gives NS their one and only trick.

A trump lead instead of a club allows a similar line. A diamond lead makes things even easier. But what if the opening lead is a spade, establishing a NS winner that can be cashed when North gets in with diamond K? There was accordingly much head scratching when Deep Finesse nevertheless asserted that 6 Hearts can be made against any defence. Pause here, if you like, to see whether you can solve this double-dummy problem which, though accidentally generated, is as challenging as many of the best compositions I have encountered over the years and hinges on what may, subject to refutation I cordially invite, be a hitherto unanalysed end-position.

After spade Q-2-7-A (S K instead from South would expose North to a simple strip squeeze) declarer crosses to heart A, trumps club 7, draws the NS trumps with heart KQ and then cashes club AKQ10, coming down to diamond AQ spade 86 opposite dummy's spade 4 diamond J6 club 9. North can do no better than keep spade J10 diamond K9, and South spade K diamond 1084.

If, when club 9 is next led from dummy, South parts with spade K, West throws spade 6 and North must discard either a diamond, whereupon West cashes diamond AQ, or a spade, when West exits with spade 6 and awaits a lead into his diamond AQ. And if, instead, South hangs on to spade K, West discards diamond Q on club 9. North, still unable to spare a spade, must (and seemingly can afford to) part with diamond 9. But now diamond 6 to diamond A drops North's diamond K, after which low to South's spade K provides a stepping stone to East's established but otherwise isolated diamond J.